3.5.64 \(\int \frac {x^{3/2}}{(a+b x)^3} \, dx\) [464]

Optimal. Leaf size=70 \[ -\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \]

[Out]

-1/2*x^(3/2)/b/(b*x+a)^2+3/4*arctan(b^(1/2)*x^(1/2)/a^(1/2))/b^(5/2)/a^(1/2)-3/4*x^(1/2)/b^2/(b*x+a)

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Rubi [A]
time = 0.01, antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {43, 65, 211} \begin {gather*} \frac {3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}-\frac {x^{3/2}}{2 b (a+b x)^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^(3/2)/(a + b*x)^3,x]

[Out]

-1/2*x^(3/2)/(b*(a + b*x)^2) - (3*Sqrt[x])/(4*b^2*(a + b*x)) + (3*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]])/(4*Sqrt[a
]*b^(5/2))

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + 1))), x] - Dist[d*(n/(b*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d, n
}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, -1] &&  !IntegerQ[n] && GtQ[n, 0]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rubi steps

\begin {align*} \int \frac {x^{3/2}}{(a+b x)^3} \, dx &=-\frac {x^{3/2}}{2 b (a+b x)^2}+\frac {3 \int \frac {\sqrt {x}}{(a+b x)^2} \, dx}{4 b}\\ &=-\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \int \frac {1}{\sqrt {x} (a+b x)} \, dx}{8 b^2}\\ &=-\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\sqrt {x}\right )}{4 b^2}\\ &=-\frac {x^{3/2}}{2 b (a+b x)^2}-\frac {3 \sqrt {x}}{4 b^2 (a+b x)}+\frac {3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}}\\ \end {align*}

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Mathematica [A]
time = 0.10, size = 59, normalized size = 0.84 \begin {gather*} -\frac {\sqrt {x} (3 a+5 b x)}{4 b^2 (a+b x)^2}+\frac {3 \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 \sqrt {a} b^{5/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^(3/2)/(a + b*x)^3,x]

[Out]

-1/4*(Sqrt[x]*(3*a + 5*b*x))/(b^2*(a + b*x)^2) + (3*ArcTan[(Sqrt[b]*Sqrt[x])/Sqrt[a]])/(4*Sqrt[a]*b^(5/2))

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Mathics [C] Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
time = 17.35, size = 590, normalized size = 8.43 \begin {gather*} \text {Piecewise}\left [\left \{\left \{\text {DirectedInfinity}\left [\frac {1}{\sqrt {x}}\right ],a\text {==}0\text {\&\&}b\text {==}0\right \},\left \{\frac {-2}{b^3 \sqrt {x}},a\text {==}0\right \},\left \{\frac {2 x^{\frac {5}{2}}}{5 a^3},b\text {==}0\right \}\right \},\frac {-3 a^2 \text {Log}\left [\sqrt {x}+\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}+\frac {3 a^2 \text {Log}\left [\sqrt {x}-\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}-\frac {6 a b \sqrt {x} \sqrt {-\frac {a}{b}}}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}-\frac {6 a b x \text {Log}\left [\sqrt {x}+\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}+\frac {6 a b x \text {Log}\left [\sqrt {x}-\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}-\frac {10 b^2 x^{\frac {3}{2}} \sqrt {-\frac {a}{b}}}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}-\frac {3 b^2 x^2 \text {Log}\left [\sqrt {x}+\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}+\frac {3 b^2 x^2 \text {Log}\left [\sqrt {x}-\sqrt {-\frac {a}{b}}\right ]}{8 a^2 b^3 \sqrt {-\frac {a}{b}}+16 a b^4 x \sqrt {-\frac {a}{b}}+8 b^5 x^2 \sqrt {-\frac {a}{b}}}\right ] \end {gather*}

Warning: Unable to verify antiderivative.

[In]

mathics('Integrate[x^(3/2)/(a + b*x)^3,x]')

[Out]

Piecewise[{{DirectedInfinity[1 / Sqrt[x]], a == 0 && b == 0}, {-2 / (b ^ 3 Sqrt[x]), a == 0}, {2 x ^ (5 / 2) /
(5 a ^ 3), b == 0}}, -3 a ^ 2 Log[Sqrt[x] + Sqrt[-a / b]] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqrt[-
a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) + 3 a ^ 2 Log[Sqrt[x] - Sqrt[-a / b]] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16
a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) - 6 a b Sqrt[x] Sqrt[-a / b] / (8 a ^ 2 b ^ 3 Sqrt[-a / b
] + 16 a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) - 6 a b x Log[Sqrt[x] + Sqrt[-a / b]] / (8 a ^ 2 b
^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) + 6 a b x Log[Sqrt[x] - Sqrt[-a /
b]] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) - 10 b ^ 2 x ^ (3
/ 2) Sqrt[-a / b] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b]) - 3
b ^ 2 x ^ 2 Log[Sqrt[x] + Sqrt[-a / b]] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqrt[-a / b] + 8 b ^ 5 x
^ 2 Sqrt[-a / b]) + 3 b ^ 2 x ^ 2 Log[Sqrt[x] - Sqrt[-a / b]] / (8 a ^ 2 b ^ 3 Sqrt[-a / b] + 16 a b ^ 4 x Sqr
t[-a / b] + 8 b ^ 5 x ^ 2 Sqrt[-a / b])]

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Maple [A]
time = 0.10, size = 50, normalized size = 0.71

method	result	size
derivativedivides	\(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\)	\(50\)
default	\(\frac {-\frac {5 x^{\frac {3}{2}}}{4 b}-\frac {3 a \sqrt {x}}{4 b^{2}}}{\left (b x +a \right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2} \sqrt {a b}}\)	\(50\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)/(b*x+a)^3,x,method=_RETURNVERBOSE)

[Out]

2*(-5/8*x^(3/2)/b-3/8*a*x^(1/2)/b^2)/(b*x+a)^2+3/4/b^2/(a*b)^(1/2)*arctan(b*x^(1/2)/(a*b)^(1/2))

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Maxima [A]
time = 0.35, size = 61, normalized size = 0.87 \begin {gather*} -\frac {5 \, b x^{\frac {3}{2}} + 3 \, a \sqrt {x}}{4 \, {\left (b^{4} x^{2} + 2 \, a b^{3} x + a^{2} b^{2}\right )}} + \frac {3 \, \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(b*x+a)^3,x, algorithm="maxima")

[Out]

-1/4*(5*b*x^(3/2) + 3*a*sqrt(x))/(b^4*x^2 + 2*a*b^3*x + a^2*b^2) + 3/4*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*
b^2)

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Fricas [A]
time = 0.31, size = 185, normalized size = 2.64 \begin {gather*} \left [-\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {-a b} \log \left (\frac {b x - a - 2 \, \sqrt {-a b} \sqrt {x}}{b x + a}\right ) + 2 \, {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{8 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}, -\frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b}}{b \sqrt {x}}\right ) + {\left (5 \, a b^{2} x + 3 \, a^{2} b\right )} \sqrt {x}}{4 \, {\left (a b^{5} x^{2} + 2 \, a^{2} b^{4} x + a^{3} b^{3}\right )}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(b*x+a)^3,x, algorithm="fricas")

[Out]

[-1/8*(3*(b^2*x^2 + 2*a*b*x + a^2)*sqrt(-a*b)*log((b*x - a - 2*sqrt(-a*b)*sqrt(x))/(b*x + a)) + 2*(5*a*b^2*x +
3*a^2*b)*sqrt(x))/(a*b^5*x^2 + 2*a^2*b^4*x + a^3*b^3), -1/4*(3*(b^2*x^2 + 2*a*b*x + a^2)*sqrt(a*b)*arctan(sqr
t(a*b)/(b*sqrt(x))) + (5*a*b^2*x + 3*a^2*b)*sqrt(x))/(a*b^5*x^2 + 2*a^2*b^4*x + a^3*b^3)]

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Sympy [A]
time = 16.54, size = 605, normalized size = 8.64 \begin {gather*} \begin {cases} \frac {\tilde {\infty }}{\sqrt {x}} & \text {for}\: a = 0 \wedge b = 0 \\\frac {2 x^{\frac {5}{2}}}{5 a^{3}} & \text {for}\: b = 0 \\- \frac {2}{b^{3} \sqrt {x}} & \text {for}\: a = 0 \\\frac {3 a^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 a^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b \sqrt {x} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {6 a b x \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {6 a b x \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {10 b^{2} x^{\frac {3}{2}} \sqrt {- \frac {a}{b}}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} + \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} - \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} - \frac {3 b^{2} x^{2} \log {\left (\sqrt {x} + \sqrt {- \frac {a}{b}} \right )}}{8 a^{2} b^{3} \sqrt {- \frac {a}{b}} + 16 a b^{4} x \sqrt {- \frac {a}{b}} + 8 b^{5} x^{2} \sqrt {- \frac {a}{b}}} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(3/2)/(b*x+a)**3,x)

[Out]

Piecewise((zoo/sqrt(x), Eq(a, 0) & Eq(b, 0)), (2*x**(5/2)/(5*a**3), Eq(b, 0)), (-2/(b**3*sqrt(x)), Eq(a, 0)),
(3*a**2*log(sqrt(x) - sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) -
3*a**2*log(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) -
6*a*b*sqrt(x)*sqrt(-a/b)/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) + 6*a*b*x
*log(sqrt(x) - sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 6*a*b*
x*log(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 10*b*
*2*x**(3/2)*sqrt(-a/b)/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) + 3*b**2*x**
2*log(sqrt(x) - sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)) - 3*b**
2*x**2*log(sqrt(x) + sqrt(-a/b))/(8*a**2*b**3*sqrt(-a/b) + 16*a*b**4*x*sqrt(-a/b) + 8*b**5*x**2*sqrt(-a/b)), T
rue))

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Giac [A]
time = 0.00, size = 72, normalized size = 1.03 \begin {gather*} 2 \left (\frac {-5 \sqrt {x} x b-3 \sqrt {x} a}{8 b^{2} \left (x b+a\right )^{2}}+\frac {3 \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 b^{2}\cdot 2 \sqrt {a b}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(3/2)/(b*x+a)^3,x)

[Out]

3/4*arctan(b*sqrt(x)/sqrt(a*b))/(sqrt(a*b)*b^2) - 1/4*(5*b*x^(3/2) + 3*a*sqrt(x))/((b*x + a)^2*b^2)

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Mupad [B]
time = 0.13, size = 58, normalized size = 0.83 \begin {gather*} \frac {3\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}}{\sqrt {a}}\right )}{4\,\sqrt {a}\,b^{5/2}}-\frac {\frac {5\,x^{3/2}}{4\,b}+\frac {3\,a\,\sqrt {x}}{4\,b^2}}{a^2+2\,a\,b\,x+b^2\,x^2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(3/2)/(a + b*x)^3,x)

[Out]

(3*atan((b^(1/2)*x^(1/2))/a^(1/2)))/(4*a^(1/2)*b^(5/2)) - ((5*x^(3/2))/(4*b) + (3*a*x^(1/2))/(4*b^2))/(a^2 + b
^2*x^2 + 2*a*b*x)

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